Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Enquiry

10:00 AM to 7:00 PM IST all days.

Business Inquiry (North)

Business Inquiry (West / East / South)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

022-62211530

Mon to Sat - 10 AM to 7 PM

a long wire with current I is bifurcated as shown in the figure dividing curent equally.The magnetic feild at point (0,a) is :

qsnImg
Asked by adityasrivastava703 5th January 2020, 10:16 PM
Answered by Expert
Answer:
Let us assume the wire along the +y-axis direction in which cureent (i/2) is passing is semi infinite with
respect to test point P(0,a), i.e, length of wire is upto +∞
 
Similarly , we assume, the wire along the -y-axis direction in which cureent (i/2) is passing is semi infinite with
respect to test point P(0,a), i.e, length of wire is upto -∞
 
 
we determine the magnetic induction due to current (i/2) passing along +y-axis direction and -ve y-axis direction separately
 
Figure given below shows the procedure of getting magnetic induction due to current (i/2) in +y-axis direction
Let us consider small current element (i/2)dy at Q(-a,y) .
 
Magnetic induction dB at  P(0,a) due to this small current element is given by ,
 
dB = [ (μo i ) / 8π ] { dy / [ (y-a)2 + a2 ] }   ......................(1)
 
Magnetic induction B due to full length of wire
 
..............................(2)
 
Similarly we calculate magnetic induction B due to current (i/2) passing in -y-direction as shown below
dB = [ (μo i ) / 8π ] { dy / [ (y+a)2 + a2 ] }   ......................(2)
 
................(3)
from eqn.(2) and (3), we see that both magnetic induction vectors are equal in magnitude but in opposite in direction.
 
Hence net magnetic induction at point P(0,a) is zero
 
Answered by Expert 6th January 2020, 8:46 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp