a light ray incident on a glass lab of thikness t .at angle thita is very small than find out latreral shift if refrative index is n
Asked by kar
18th June 2018,
11:03 PM
Answered by Expert
Answer:
Figure shows the lateral shift of incident light ray on a glass slab due to refraction.
Let i and r be the angle of incidence and angle of refraction respectively.
in ΔABC, we have, tan r = BC / AB = BC / t ........................(1)
where t is thickness of glass slab.
in ΔABD, we have , tan i = BD / AB = (BC + CD) / AB = (BC / t) + ( l / t ) ..................(2)
where l is lateral shift.
from equations (1) and (2), we can write, tan i - tan r = l / t ........................(3)
For small angles, tangent can be replaced by sine. Hence we rewrite eqn.(3) as
sin i - sin r = l / t ..................................(4)
if n is refractive index of material of slab, then we have ( sin i / sin r ) = n ...................(5)
By eliminating sin r in eqn.(4) using eqn.(5), we have 
.................(6)
.................(6)hence lateral shift l is given by, 
Answered by Expert
19th June 2018,
11:34 AM
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