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CBSE Class 9 Answered

A JUGGLER THROWS BALL VERTICALLY UP AT AN INTERVAL OF 1 s. HIS MAX SPEED OF THROW SO THAT SIX BALL IN AIR IS ----------. g = 10m / s SQUARE
Asked by haroonrashidgkp | 16 Jul, 2018, 08:07: PM
answered-by-expert Expert Answer
6 balls thrown at interval of 1 second are in air, that means the first ball reaches the maximum height 6 secs after it is thrown.
 
we have eqn. " v = u - g×t ", v is final speed that is zero when the ball reaches maximum height,
u is intial speed, g is acceleration due to gravity and t is time
 
hence u = 10×6 = 60 m/s
Answered by Thiyagarajan K | 17 Jul, 2018, 05:00: PM

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