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A IS A POINT AT A DISTANCE OF 12CM FROM CENTRE O OF A CIRCLE OF RADIUS5CM.AP AND AQ ARE THE TANGENTS TO THE CIRCLE AT  P AND Q RESPECTIVELY.IF A TANGENT BC IS DRAWN AT A POINT R LYING ON MINOR ARC PQ TO A  POINT  INTERSECTING AP AT B AND AQ AT C.FIND THE PERIMEYTER OF TRIANGLE ABC

Asked by shabnakader 7th October 2017, 11:08 AM
Answered by Expert
Answer:
begin mathsize 16px style OA equals 13 space cm comma space Radius equals OP equals 5 space cm
Since space AP space is space straight a space tangent space to space the space circle space with space centre space straight O
and space OP space is space its space radius comma space OP perpendicular PA.
In space increment OPA comma space angle OPA equals 90 degree
AP squared equals OA squared minus OP squared equals 13 squared minus 5 squared equals 144
rightwards double arrow AP equals 12 space cm
Now comma space AP equals 1 half cross times Perimeter space of space triangle ABC
rightwards double arrow 12 equals 1 half cross times Perimeter space of space triangle ABC
rightwards double arrow Perimeter space of space triangle ABC equals 24 space cm
end style
Answered by Expert 4th December 2017, 3:29 PM
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