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ICSE Class 10 Answered

A hot solid of mass 60g at 100°C is placed in 100g of water at 18°C. The final temperature recorded is 20°C. Find the specific heat capacity of the solid.
Asked by saibaba1069 | 01 Jan, 2021, 11:26: PM
answered-by-expert Expert Answer
Heat energy gained by water = mass of water × specific heat of water × increase in temperature
 
Heat energy gained by water = 100 × 10-3 × 4186 × (20-18) = 837.2 J
 
Specific heat of water = 4186 J / ( kg K )
 
Heat energy lost by solid = mass of solid × specific heat of solid × decrease in temperature
 
Heat energy lost by solid = 60 × 10-3 × S × (100-18) = ( 4.92 S )  J
 
where S is specific heat of solid
 
By conservation of energy , heat gain by water = heat lost by solid
 
4.92 S = 837.2 J   or   S = 170 J (kg K )
Answered by Thiyagarajan K | 02 Jan, 2021, 09:03: AM

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