CBSE Class 12-science Answered
A heavy nucleus X of mass number 240 and
binding energy per nucleon 7.6 MeV is split into two fragments Y and Z of
mass numbers 110 and 130. The binding energy of nucleons in Y and Z is 8.85
MeV per nucleon. Calculate the energy Q released per fission in MeV.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Given that X (A = 240) with BE/nucleon= 7.6 MeV/nucleon undergoes fission to release two daughter nuclei: Y (A=110) and Z (A = 130) with BE/nucleon of both being 8.5 MeV/nucleon.
For the fission to happen:
Total BE of X= 240 x 7.6 = 1824 MeV
Total BE of (Y+Z) = (110+130) x 8.5 = 2040 MeV
Energy released in the fission = 2040 - 1824 = 216 MeV
Energy released per fission = 216/240= 9.9 MeV
Answered by | 04 Jun, 2014, 03:23: PM
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