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CBSE Class 9 Answered

A hammer of mass 500g moving with 50m/s strikes a nail.this stops the hammer in a small time interval of 0.01 second.what is the change in momentum suffered by the hammer?also calculate the force of hammer on the nail.what will be the force of nail on the hammer.give reason for your answer
Asked by hridhyavijay | 08 Feb, 2019, 07:43: PM
answered-by-expert Expert Answer
Initial momentum = 0.5×50 = 25 kg-m/s
final momentum is zero. Hence change in momentum = 25 kg-m/s
 
force of hammer on the nail = rate of change of momentum = d(mv)/dt = 25/0.01 = 2500 N
 
force of nail on hammer = 2500 N.
 
As per Newton's third law forces always occur in pair. 
When hammer transmits a force on nail, equal reaction force is transmitted by nail to hammer
Answered by Thiyagarajan K | 08 Feb, 2019, 08:05: PM
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