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ICSE Class 9 Answered

  A gas is enclosed in a vessel at standard temperature. At what temperature, the volume of enclosed gas will be 1/6 of its initial volume, given that the pressure remains constant.
Asked by shriyagupta006 | 18 Jun, 2019, 09:00: PM
answered-by-expert Expert Answer
Given:
 
T1 = 273 K
 
Let the initial volume, V1 = x 
 
Final volume, V2 = straight x over 6
 
According to the Charle's law,
 
straight V subscript 1 over straight T subscript 1 space equals space straight V subscript 2 over straight T subscript 2 straight x over 273 space equals space fraction numerator begin display style bevelled straight x over 6 end style over denominator straight T subscript 2 end fraction straight T subscript 2 space equals space straight x over 6 cross times 273 over straight x straight T subscript 2 space equals space 45.5 space straight K
 
       = 45.5 − 273 
 
       = -227.5 °C
 
The temperature will be −227.5°C.
Answered by Varsha | 19 Jun, 2019, 11:07: AM

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