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Home / Doubts and Solutions/NEET/Physics

A Gas expands with temperatures according to the relation V=KTpower 2/3.where K is a constant. Calculate work done when the temperature changes by 60k.a-10R,b-30R,c-20R,d-40R

Asked by Priyanka 7th November 2017, 2:50 PM
Answered by Expert
Answer:
f r o m space d e f i n i t i o n space o f space w o r k d o n e d W equals P d V equals fraction numerator R T over denominator V end fraction d V space space equals fraction numerator R T over denominator K T to the power of begin display style 2 over 3 end style end exponent end fraction d V minus negative negative negative negative negative negative negative negative negative negative negative 1 V equals K T to the power of 2 over 3 end exponent t a k i n g space d e r i v a t i v e d V equals K 2 over 3 T to the power of fraction numerator negative 1 over denominator 3 end fraction end exponent d T P u t t i n g space i n space 1 space a n d space i n t e g r a t i n g w equals 2 over 3 R integral subscript T subscript 1 end subscript superscript T subscript 2 end superscript d T equals 2 over 3 R left parenthesis T 2 minus T 1 right parenthesis equals 2 over 3 R X 60 equals 40 R O p t i o n space D
Answered by Expert 6th December 2017, 3:48 PM
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