Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

A frictionless track ends in a circular loop of radius R.A body slides down the track from a point A which is at a height 5cm .Max value of R for the body to successfully complete a loop?

Asked by 28th March 2013, 12:24 PM
Answered by Expert
Answer:
mgh=PE at h
mgh=1/2 mv2 =KE at B
at B=1/2 mv2=mg(2R)...energy conservation law applied in circular loop
v2=4R
 
mgh=1/2 mv2
mgh=(1/2) m 4R
R max=gh/2
Answered by Expert 15th April 2013, 4:36 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp