CBSE Class 9 Answered
A freely falling body covers half of its distance in the last 1 second of its journey. then find the total time taken to reach the ground
Asked by Akshit Srivastava | 16 Oct, 2013, 09:23: AM
Expert Answer
A body is falling freely. Thus, u = 0 m/s, g = 10 m/s2.
Let the total time to hit the ground be t.
Let the distance from top to ground be h
Thus, we have
h = ut + ½gt2 = ½gt2 ...... (1)
Now, half distance is covered in last 1 second. Hence, first half distance is covered in (t -1) seconds.
Thus, distance from top to half way is given as
h/2 = ½g(t-1)2
h = g(t-1)2 ...... (2)
Equating equations 1 and 2, we get
Answered by Romal Bhansali | 17 Oct, 2013, 09:40: AM
Application Videos
Concept Videos
CBSE 9 - Physics
Asked by mailtoparvathyprajith | 06 Feb, 2024, 09:50: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by mailtoparvathyprajith | 06 Feb, 2024, 09:10: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by sapnamantri05 | 24 Nov, 2023, 04:54: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by ashrithpandu84 | 09 Oct, 2023, 08:09: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by janhavisoni2099 | 02 Oct, 2023, 05:20: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by durgesh21332 | 06 Sep, 2023, 06:17: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by sagrawal0081 | 18 Aug, 2023, 05:04: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by ketkiparasgandhi | 05 Jul, 2023, 08:02: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by leena3732 | 15 Jun, 2023, 09:42: AM
ANSWERED BY EXPERT