CBSE Class 10 Answered
A faster train takes one hour less than slower train for a journey of 200km.if the speed of a slower train is 10km/hr less than of a faster train find the speed of a two trains
Asked by suryakarthik2003 | 19 Feb, 2019, 07:21: AM
Expert Answer
Let the speed of fast train is x km/hr. Hence slow train speed (x-10) km/hr
time taken by fast train = ( 200/x ) hour , time taken by slow train = [ 200/(x-10) ] hour
Given : 200/x = [ 200/(x-10) ] +1 = (200+x-10)/(x-10)
200(x-10) = (190+x)x = 190x + x2
x2 -10x + 2000 = 0
(x-50)(x+40) = 0 hence possible solution for x is : x = 50
Hence speed of fast train = 50 km/hr ; speed of slow train = 40 km/hr
Answered by Thiyagarajan K | 19 Feb, 2019, 11:18: PM
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