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A dielectric slab of length l, width b, thickness d and dielectric constant k fills the space inside a parallel plate capacitor. At t=0 the slab begins to be pulled out slowly with speed v. At time t the capacity of the capacitor is

 

Asked by Deepak 4th August 2018, 10:44 PM
Answered by Expert
Answer:
If the dielectirc slab is pulled with velocity v, then after time t,
we have two parallel plate capacitors that are connected in parallel as shown in figure.
 
Length of the plate for the capacitor filled with dielectric is (l-vt) and air filled capacitor is v×t
 
hence the effective capacitance at time t  = begin mathsize 12px style equals space k epsilon subscript o fraction numerator open parentheses l space minus space v cross times t close parentheses cross times b over denominator d end fraction space plus space epsilon subscript o fraction numerator v cross times t cross times b over denominator d end fraction space end style
Answered by Expert 5th August 2018, 8:41 AM
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