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A cylindrical tub of radius 12 cm contains water to a depth of 20 cm. A spherical ball is dropped into the tub raising the level of water by 6.75 cm. What is the radius of the ball?

Asked by Topperlearning User 7th April 2014, 10:34 AM
Answered by Expert
Answer:

Let r be the radius of the spherical ball.

When spherical ball is dropped into the tub, the level of water raises by 6.75 cm.

Volume of spherical ball = Volume of water displaced in the cylindrical tub

r3 =

r3 = 729 cm3

r = 9 cm

Answered by Expert 7th April 2014, 12:34 PM
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