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# A cylinder of height h is placed on an inclined plane it just begins to slide on increasing angle of 45degrees what is the radius of the cylinder

Asked by sandhyamsani 20th March 2017, 7:33 PM

• The force of friction 'f' is the force that is responsible for producing the translatory equilibrium (the state of equilibrium in which the motion changes dynamically).
• But it also produces a torque which tries to overturn the block=
• The restoring torque due to normal reaction 'N' opposes this through a distance 'x'.
• Therefore, for 'no overturning of the cylinder' is
• As the angle of inclination of surface increases, the friction also increases but the normal reaction (N) decreases.
• Due to the decrease in normal reaction, the chances of overturning increases.

• To counterbalance the overturning, N has to shift up to an extreme level of x=r, where r is the radius of the given cylinder.
• Therefore for 'just' no overturning.
• This condition is only possible at angle=45 degree.
• As, f (f= mg Sin)=N (mg Sin), thus .
Answered by Expert 21st March 2017, 5:56 PM
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