ICSE Class 10 Answered
A cricket ball of mass 100 g moving with a velocity of 90 km per hour is brought to rest by a player by moving his hands back by 40 cm find impulse and time in which ball come to rest and force exerted by player
Asked by Samrat | 29 Jun, 2018, 10:38: PM
Expert Answer
speed = 90 km/hr = 90 × (5/18) = 25 m/s
retardation a produced to stop the ball is obtained by using the formula " v2 = u2-2aS ",
where v is final speed that is zero in this case. u is initial speed and S is the distance.
a = u2 / (2S) = (25 × 25 )/ (2×40×10-2) = 781,25 m/s2
Time t to stop the ball is obtained using the formula " v = u - a×t " ;
hence t = u/a = 25/781.25 = 32 milli seconds
Force exterted by player = mass × acceleration = 100×10-3×781.25 = 78.125 N
impulse = Force×time = 78.125×32×10-3 = 2.5 N s
Answered by Thiyagarajan K | 30 Jun, 2018, 05:38: AM
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