CBSE - XI Science - Physics - Mechanical Properties of Solids
a Copper wire of negligible mass 1m long and cross sectional area 0.000001m^2 is kept on a smooth horizontal table with 1 end fixed. A ball of mass 1Kg is attached to the other end. The wire and the ball are rotating with an angular velocity of 20 rad/s. If the elongation of the wire is 0.001m. Find Young Modulus of wire? If on increasing the velocity to 100 rad/s the wire breaks down. Find the breaking Stress?
In this case F is a combination of the centripetal force and the gravitational force.
F = mrw^2 +mg where w is the angular velocity
= 1 * 0.001/sqrt(pi) * (20)2 + 1 * 9.8
Rate this answer
You have rated this answer /10