CBSE Class 11-science Answered
A copper wire of length 2.2m and a steel wire of length 1.6m,both of diameter 3.0mm, are connected end to end, when stretched by a load, the net elongation is found to be 0.70mm .obtain the load applied.
Asked by Jisha Mary Thomas | 16 Oct, 2013, 06:11: PM
Expert Answer
Length of copper wire Lc= 2.2 m
Length of steel wire Ls = 1.6 m
Diameter d = 3 mm = 3 × 103 m
Cross sectional are =
Net elongation (lc + ls) = 0.70 mm = 7 × 104 m ....(1)
Let load applied is F.
Ys = 2.0 × 1011 N/m2
Tc = 1.3 × 1011 N/m2
Apply (2) and (3)
Plug in the values
From (1) and (4)
From Equation (2)
Answered by Faiza Lambe | 16 Oct, 2013, 10:03: PM
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