Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

A copper wire of length 2.2m and a steel wire of length 1.6m,both of diameter 3.0mm, are connected end to end, when stretched by a load, the net elongation is found to be 0.70mm .obtain the load applied.

Asked by Jisha Mary Thomas 16th October 2013, 6:11 PM
Answered by Expert
Answer:

Length of copper wire Lc= 2.2 m

Length of steel wire Ls = 1.6 m

Diameter d = 3 mm = 3 103 m

Cross sectional are =

 

                          

Net elongation (lc + ls) = 0.70 mm = 7 104 m    ....(1)

Let load applied is F.

Ys = 2.0 1011 N/m2

Tc = 1.3 1011 N/m2

 

Apply (2) and (3)

 

Plug in the values

 

From (1) and (4)

 

From Equation (2)

 

 

Answered by Expert 16th October 2013, 10:03 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer 2/10

Your answer has been posted successfully!

Free related questions

15th March 2017, 12:35 PM
15th March 2017, 10:53 AM
19th March 2017, 5:52 PM
17th March 2017, 4:25 PM
17th March 2017, 7:02 PM

Chat with us on WhatsApp