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A constant force acts on a body of mass 0.9kg  at rest for 10s. If the body moves a distance of 250m, the magnitude of the force is

Asked by jahnavibandaru04 19th April 2020, 8:57 AM
Answered by Expert
We know, 
Second equation of motion is given as, 
s = ut +(1/2) at2 
s = 250 m, u = 0, t = 10 s 
S u b s t i t u t i n g space t h e space v a l u e s comma space w e space g e t comma space
250 space equals space 0 space cross times 10 space plus space 1 half cross times a cross times open parentheses 10 close parentheses squared
a space equals space fraction numerator 250 cross times 2 over denominator 100 end fraction space equals space 5 space m divided by s squared space

W e space k n o w comma space
F space equals space m cross times a
m space equals space 0.9 space k g comma space a space space equals space 5 space m divided by s squared
F space space equals space 0.9 space cross times space 5 space equals space 4.5 space N
Answered by Expert 19th April 2020, 3:58 PM
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