###### Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Enquiry

10:00 AM to 7:00 PM IST all days.

Business Inquiry (North)

Business Inquiry (West / East / South)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

022-62211530

Mon to Sat - 10 AM to 7 PM

# A cone is falling at a speed of vo strikes and penetrates a block.The acceleration of the cone after the impact is - a=g-cx2 where c is a positive constant and x is penetration distance.If the maximum penetration distance is xm.Then find the value of xm

Asked by anujrudrakar25 19th August 2018, 11:26 PM
Answered by Expert
Answer:
The required equation of motion to solve this question is " V2 = u2 - 2×a×S " .
where v is final velocity which is zero in this case, u is initial velocity which is given as vo,
a is retardation  and S is the the stopping distance which is given as xm .

then we have ,  0 = vo2 - 2×a×xm     or    .................(1)
Eqn.(1) is cubic that can be solved only by numerical method by substituting the values of vo, g and c
Answered by Expert 20th August 2018, 11:31 AM
Rate this answer
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10

Tags: distance
Your answer has been posted successfully!
RELATED STUDY RESOURCES :
JEE QUESTION ANSWERS

### Latest Questions

CBSE XII Commerce Accountancy
Asked by sakshiarora2607 18th February 2020, 12:25 AM
CBSE X Biology
Asked by vishnutripathi36 18th February 2020, 12:13 AM