CBSE Class 11-science Answered
A compound H2X with molar weight of 80 g is dissolved in a solvent having density of 0.4 g/ml. Assuming no change in volume upon dissolution, the molality of a 3.2 molar solution is
Asked by Anil | 23 May, 2017, 02:53: PM
Expert Answer
Solution:
In 3.2 molar solution,
We have amount of solute = 3.2 mol
Volume of solution = 1.0 L
Since there occurs no change in volume on dissolving solute,
Volume of solvent = 1L
Mass of solvent = (1.0L)(0.4 gmL-1)
= (103mL)(0.4 gmL-1)
=400 g =0.4kg
Molality of the solution = 3.2/0.4 =8molkg-1
Answered by Vaibhav Chavan | 23 May, 2017, 04:29: PM
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