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CBSE Class 12-science Answered

A compound AB crystallises in the bcc lattice with unit cell edge length of 390pm. Calculate the distance between the oppositely charged ions in the lattice and radius of A if B is 175pm.
Asked by hilhew7 | 13 Sep, 2015, 11:00: AM
answered-by-expert Expert Answer
begin mathsize 11px style For space BCC space lattice colon Edge space length space left parenthesis straight a right parenthesis space equals space fraction numerator 2 straight d over denominator square root of 3 end fraction space therefore space straight d space equals space fraction numerator square root of 3 over denominator 2 end fraction space cross times space straight a space equals space fraction numerator square root of 3 over denominator 2 end fraction space cross times space 390 space equals space bold 337 bold. bold 75 bold space bold pm bold.  left parenthesis ii right parenthesis space straight r subscript straight A superscript plus space space plus space straight r subscript straight B superscript minus space equals space 337.75 therefore space straight r subscript straight A superscript plus space space equals space 337.75 space minus space space straight r subscript straight B superscript minus space equals space 337.75 space minus space 175 space equals bold space bold 162 bold. bold 75 bold space bold space bold pm bold. end style
Answered by Arvind Diwale | 13 Sep, 2015, 04:45: PM
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