ICSE Class 8 Answered
A Certain piece of metal has a mass of 282.6g, when it is immersed it displaces the water (at 4°C) of mass equal to 20g. What is the RD of the metal piece.
Asked by Cl_narayan | 18 Jun, 2019, 09:44: PM
Expert Answer
Volume of displaced water is same as the volume of immersed metal piece.
Volume of displaced water = mass/density = 20g / 1 g-cm-3 = 20 cm3
Hence density of metal piece = mass/volume = 282.6 g / 20 cm3 = 14.13 g/cm3
Answered by Thiyagarajan K | 18 Jun, 2019, 10:17: PM
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