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a centigrate and farhenite thermometer are dipped in boiling water .the water temp is lowered untill the farhenite thermometer resister 140degree.whwt is the fall in temp as resisterde by centigrade thermometer?a-30degree,40degree,60degree,80degree
 
 
 

Asked by Priyanka 13th November 2017, 4:39 PM
Answered by Expert
Answer:
Farenheat to centigrade conversion is (5/9)(F-32) = C.
Now farenheat reading is 140, hence C = (5/9)(140-32) = (5/9)×108 = 60°C.
 
since initial temperature was 100 °C, fall in temperature is 40°C
Answered by Expert 4th January 2018, 10:26 PM
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