CBSE Class 12-science Answered
A cell of emf E and internal resistance r is connected to two external resistances R1 and R2 and a perfect ammeter. The current in the circuit is measured in four different situations:
(i) Without any external resistance in the circuit
(ii) with resistance R1 only
(iii) With R1 and R2 in series combination
(iv) with R1 and R2 in parallel combination
The currents measured in the four cases are 0.42 A, 1.05A, 1.4 A and 4.2A, but not necessarily in that order. Identify the current corresponding to the four cases mentioned above.
Asked by Topperlearning User | 01 Jul, 2014, 03:44: PM
Expert Answer
current in case I
(i)
(ii) current in case II
(iii) current in case III
(iv) current in case IV
Logically from the above expressions,
i3 < i2 < i4 < i1
So, i1 = 4.2 A
i4 = 1.4 A
i2 = 1.05 A
i3 = 0.42 A
Answered by | 01 Jul, 2014, 05:44: PM
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