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CBSE Class 12-science Answered

A cell of emf 8 V and internal resistance of 0.5 ohm is connected across a load of resistance (i) 15.5 ohm (ii) 11.5 ohm. Calculate the potential drop in each case.
Asked by Topperlearning User | 22 Apr, 2014, 04:50: PM
answered-by-expert Expert Answer

(i) When the load resistance is 15.5 ohm

V1 = E - I1r
V1 = 8 - (0.5 × 0.5)
V1 = 7.75 V

(ii) When the load resistance is 11.5 ohm

V2 = E - I2r

V2 = 8 - (0.66 × 0.5)

V2 = 7.67 V

Answered by | 22 Apr, 2014, 06:50: PM

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