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A car is moving on a straight road covers one third of its distance with a speed of20 km/h &rest with a speed of 60km/h along straight line the avarege  speed of car is?

Asked by Borkarvaibhav52 5th July 2019, 8:06 PM
Answered by Expert
Answer:
Let the distnace travelled by a car on staright path  be x.
The one thrid distance is covered with speed of 20 km/h and the rest two- third distance with speed of 60 km/h
Thus, 
time required for the one third of the journey is 
fraction numerator begin display style bevelled x over 3 end style over denominator 20 end fraction equals x over 60 
The time required for the rest part of the journey is 
fraction numerator begin display style bevelled fraction numerator 2 x over denominator 3 end fraction end style over denominator 60 end fraction equals x over 90 
Thus the total time taken to complete the journey is,
x over 60 plus x over 90 equals x over 36  
Thus, the average speed is,
 
Average speed = Total distance travelled/ total time taken 
A v e r a g e space s p e e d space equals space fraction numerator x over denominator begin display style bevelled x over 36 end style end fraction
T h u s space a v e r a g e space s p e e d space space equals 36 space k m divided by h space
Answered by Expert 6th July 2019, 1:49 PM
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