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# A→→C(Half life=1 minute), B→→C(Half life=2minutes). At t=0, concentration of A was 4N｡ whereas concentration of B was N｡ at t=0. Find- (i) the concentration of C at the instance when concentration of A and B becomes equal. Also find(ii) the concentration of C at the instance when activity of A becomes equal to activity of B.

Asked by patra04011965 30th March 2020, 8:02 PM
Concentration of A at time t ,  ........................  (1)
Concentration of B at time t , .........................( 2 )
where λA is decay constant of A and it is given by, λA = ln2 min-1
where λB is decay constant of B and it is given by, λB = (1/2) ln2 min-1

Time t for getting equal concentration of A and B is obtained by equating above equation and solving for time t

If NA = NB ,  then we have ,

Hence concentration of C at t = 4 min  given by,
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Activity of A ,
Activity of B ,
If both activities are equal, then we have,

Hence concentration of C at t = 6 min  given by,
Answered by Expert 30th March 2020, 10:40 PM
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