CBSE Class 9 Answered

Given:

Initial speed of the bus, u= 0

Acceleration, a = 0.1 m s^-2

Time taken, t = 2 minutes =2 × 60 s =  120 s

Speed acquired, v = ?

Distance travelled, s = ?

(a) v= u + at

     v = 0 + 0.1 × 120

     v  = 12 m s^–1

Thus, speed acquired by the bus is 12 m s^-1.

(b) According to the equation of motion:

     v² = u²+ 2as

     v² - u²= 2as     [where, s is the distance covered by the bus]

    (12)² - (0)²= 2(0.1) s

    144 = 0.2 s

    s = 144 / 0.2

   s = 720 m = 7.2 × 10² m

Thus, distance travelled by the bus is 720 m.