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A bullet weighing 50 grams leaves the gun with a velocity of 30m/s. The ratio of momentum of the bullet to the gun is what?
Asked by aahnik.mohanty | 27 Nov, 2017, 08:10: PM
answered-by-expert Expert Answer
 the momentum of the bullet = 0.05 kg x 30 m/s = 1.5 kgm/s
 
By newtons third law
 
the bullet will exert equal and opposite reaction on gun 
 
the momentum of gun= -1.5 kgm/s
 

the ratio of the momentum of the bullet to the gun = 1.5/-1.5= -1
Answered by Gajendra | 28 Nov, 2017, 04:08: PM

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