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a bullet of mass 5g travels with a speed of 500m/s . if it penetrates a fixed target if it offers a constant resistant force to the motion of the bullet . find the initial K.E of bullet distance through which bullet has penetrated ?

Asked by ayush kumar 23rd January 2011, 7:20 PM
Answered by Expert
Answer:
Dear student,
 
K.E = 1/2 m v ^2
 
= 0.5X0.005X500X500 = 625J
 
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Answered by Expert 2nd February 2011, 1:22 PM
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