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ICSE Class 9 Answered

A bullet fired with speed 100 ms-1 travels 500 m in air.Assuming the air fmingmriction to be constant,calculate the retardation prodced by the air.and how much velocity of bullet after 1.2 s of motion? Its velocity is coming 488 bevelled m over s Please tell me how it come  
Asked by ayushmani1871 | 27 Jul, 2019, 12:17: PM
answered-by-expert Expert Answer
If we apply the equation, v2 = u2-2aS  , we can get retardation a .
In this equation v is final speed which is zero hero because the bullet is stopped at end,
u is inital speed and S is distance travelled before bullet is stopped
 
hence retardation a = u2 / ( 2S)  = (100×100)/(2×500)  = 10 m/s2
 
velocity after 1.2s, v = u - a t  = 100 - (10×1.2) = 88 m/s
Answered by Thiyagarajan K | 27 Jul, 2019, 03:42: PM
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