A box contains two different white balls, three different black balls and four different red balls. In how many ways can three balls be drawn from the box if atleast one black ball is to be included in the draw?
Asked by sakshisingh3124
26th April 2018,
10:22 AM
Answered by Expert
Answer:
Required number of ways = number of ways of drawing 1 black and 2 non-black) + number of ways of drawing 2 black and 1 non-black + number of ways of drawing 3 black)
= 3C1 6C2 + 3C2 6C1 + 3C3
After solving we get answer as 64.
Answered by Expert
26th April 2018,
1:19 PM
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