1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

022-62211530

Mon to Sat - 11 AM to 8 PM

# A box contains 20 balls bearing numbers 1, 2, 3, 4 … 20. A ball is drawn at random from the box. What is the probability that the number on the ball is(i) divisible by 2 or 3(ii) not divisible by 10?

Asked by Topperlearning User 27th July 2017, 4:28 PM

Total number of outcomes = 20

(i) Numbers "divisible by 2" are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, i.e., 10 in number.

Numbers "divisible by 3" are 3, 6, 9, 12, 15, 18, i.e., 6 in number.

Number "divisible by 2 and 3" are 6, 12, 18, i.e., 3 in number.

Number of favourable outcomes = 3

\\Required probability ==

(ii) Numbers divisible by 10 are 10, 20, i.e., 2 in number.

\\ Numbers which are not divisible by 10 = 20 - 2 = 18

\\ Required probability =

Answered by Expert 27th July 2017, 6:28 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10