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A BOUNCING TENNIS BALL REBOUNDS EACH TIME TO A HEIGHT ONE HALF THAT OF THE PREVIOUS ONE.IF IT IS DROPPED FROM A HEIGHT OF 3m,THE TOTAL DISTANCE TRAVELLED BY THE BALL BEFORE COMING TO REST IS-

Asked by architsrivastava02 19th February 2011, 12:14 PM
Answered by Expert
Answer:
Dear student,
 
distance of 1st bounce = 3m
distance of 2nd bounce = 1.5m
distance of 3rd bounce = 0.75m
distance of 4th bounce = 0.37m
distance of 5st bounce = 0.18m
distance of 6th bounce = 0.09m
distance of 7th bounce = 0.04m
distance of 8th bounce = 0.02m
distance of 9th bounce = 0.01m
 
total distance travelled = 5.69m
 
check with this:
 
3 + 2(3)(0.5)(0.5^9 -1)/(0.5-1)= 3+5.98 approx= 6, = 9m
 
Thanking you
 
Team
Topperlearning.com
 
 
 
Answered by Expert 16th March 2011, 3:18 PM
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