A bomb is dropped on an enemy post by an aeroplane flying with a horizontal velocity of 60 km per hour and at a height of 490 m how far the aeroplane must be from the enemy post at time of dropping the bomb so that it may directly hit the target
Asked by thamburuesanthosh
28th March 2018,
10:51 PM
Answered by Expert
Answer:
When the bomb is dropped from fighter plane, horizontal component speed u is 60 km/hr, vertical speed v is zero(assumed the bomb is just dropped). After ejected out, the bomb is subjected to acceleration in vertical direction due to gravity, but horizontal speed remains same.
time taken t by the bomb to reach ground level is given by 
speed in horizontal direction u = 60 km/hr = (60×5)/18 m/s = 50/3 m/s
distance to be travelled in horizontal direction = (50/3)×10 = 500/3 m = 166.6 m
Answered by Expert
29th March 2018,
7:58 AM
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