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A body of mass 2 kg is dropped from the top of a tower of height 50m.Acceleration due to gravity is 10m/s2. Calculate its kinetic energy at the end of 2 s.

Asked by sujaysarkar84 4th March 2015, 6:32 PM
Answered by Expert
Answer:

begin mathsize 14px style Hi space Sujay comma The space velocity space of space the space body space after space 2 space straight s space is straight v equals straight u plus at equals 0 plus 10 cross times 2 equals 20 space straight m divided by straight s So comma space kinetic space energy space after space the space end space of space 2 space seconds space is straight K equals 1 half mv squared equals 1 half cross times 2 cross times 20 squared equals 400 space straight J end style

Answered by Expert 4th March 2015, 6:43 PM
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