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A body is projected with a speed u at an angle of 30 with the horizontal at t=0 the angular momentum of a body about the point of projection is x√3mu^3/64g at t= 3u/4g find value of x
Asked by harshitj291 | 14 Mar, 2019, 08:27: PM
Expert Answer
if we compare the angular momentum as given by eqn.(6) with the given expression (x√3/64) m u3 /g , we get x = -2√3 (√3 + 1 )
Answered by Thiyagarajan K | 15 Mar, 2019, 09:55: AM
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