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A body is projected horizontally with a vertical of 4ms-1 from the top of a high tower .The velocity of the body after 0.7s is nearly:g=10ms-2


Asked by valavanvino1011 10th August 2018, 6:14 AM
Answered by Expert
Horizontal componenet uof velocity is unaffected.

At starting point, vertical component of velocity is zero.

After 0.7 s vertical component of velocity uis given by, uy = g×t = 10×0.7 = 7 m/s

velocity of the body after 0.7s  = begin mathsize 12px style square root of 4 squared plus 7 squared end root space almost equal to space 8 space m divided by s end style
Answered by Expert 10th August 2018, 12:00 PM
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