A block of mass 15kg is resting on a rough inclined plane as shown.The block is tied up by a horizontal string which has a tension of 50N.Calculate the coefficient of friction bet the block and inclined plane.
Asked by m.nilu
14th August 2018,
10:31 PM
Answered by Expert
Answer:
Figure shows the forces acting on the 15 kg block that is resting on the inclined plane.
Resolved comonents along the direction parallel and perpendicular to inclined plane are also shown in figure.
At Equilibrium, from the forces perpendicular to inclined plane, we can write, 15gcos45 + 50sin45 = N ......................(1)
At Equilibrium, from the forces parallel to inclined plane, we can write, 15gsin45 = μN+50cos45 ..................(2)
N is normal reaction force, that can be calculated from eqn.(1).
By substituting N in eqn.(2), we can calculate the coefficient of friction from eqn.(2). we get μ = 0.49
Answered by Expert
15th August 2018,
11:08 AM
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