a ball is vertically upward from the ground and a student gazing out of the window sees it moving upward past him at 10 m/s.the window is at 15 m above the ground.the velocity of the ball 3s after it was projected from the ground is
Asked by 443879616104558
22nd August 2018,
10:47 AM
Answered by Expert
Answer:
From the information given in the question, we know that vertically projected ball reaches the velocity 10 m/s at a height of 15 m.
Let us use the equation of motion, " v2 = u2 - 2×g×h ", where u is initial velocity and v is the velocity at height h.
then we have, 102 = u2 - 2×9.8×15, or u = 19.85 m/s
velocity after 3 s is obtained from "v = u - g×t ", hence v = 19.85 - 9.8×3 = -9.55 m/s
hence after 3 seconds, the ball is falling downwards with speed 9.55 m/s
Answered by Expert
22nd August 2018,
2:24 PM
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