Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

A ball is thrown vertically upwards with a given velocity 'u' such that it rises for T seconds(T>1), what is the distance travelled by the ball during the last one second of ascent (in metres)? (Acceleration due to gravity is g m/second square)

Asked by adityaahuja099 11th October 2017, 7:07 PM
Answered by Expert
Answer:
 
begin mathsize 16px style Velocity space at space the space toppest space space point space left parenthesis time space straight t right parenthesis space is space zero
therefore space straight v equals straight u minus gt
0 equals straight u minus gt
straight u equals gt
straight t equals straight u over straight g end style
 
begin mathsize 16px style Velocity space at space time space straight t minus 1
straight v equals straight u minus straight g left parenthesis straight t minus 1 right parenthesis
straight v equals gt minus gt plus straight g
straight v equals straight g end style
 
begin mathsize 16px style Distance space traveled space in space last space one space second space left parenthesis straight t equals 1 right parenthesis
straight s equals left parenthesis velcoity space at space time space straight t minus 1 right parenthesis straight t minus 1 half gt squared
equals gx 1 minus 1 half xgx 1 squared
equals straight g over 2 end style

Answered by Expert 27th November 2017, 6:32 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Free related questions

13th December 2017, 7:26 PM