Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

A ball is thrown horizontally from a cliff such it  strikes the ground after 5s. The line of sight makes an angle 37° with the horizontal . The initial velocity of projection in ms-1 is

Asked by valavanvino1011 11th August 2018, 4:07 AM
Answered by Expert
Answer:
As shown in figure, if projectile strikes the ground by making an angle 37º with horizontal direction,
then at the point of hitting ground, resolved horizontal componenet uh of projectile velocity
and the vertical component uv are related as,   ( uv / uh) = tan 37
 
uv is the velocity gained due to gravity after 5 s from the time of projection and it is given by, uv = g×t = g×5.
(Initial vertical component of velocity is zero, because of horizontal projection).

then begin mathsize 12px style u subscript h space equals space fraction numerator g cross times 5 over denominator tan 37 end fraction space equals space fraction numerator 9.8 cross times 5 over denominator tan 37 end fraction space equals space 65 space m divided by s end style
Answered by Expert 11th August 2018, 6:45 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer 10/10

Your answer has been posted successfully!

Chat with us on WhatsApp