Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
For Business Enquiry


Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number


Mon to Sat - 11 AM to 8 PM

A ball is placed near the periphery of a merry-go-round and is  tied to its centre. Merry-go-round  is rotating about an axis passing through its centre.

1. What will be your observation when you are standing outside the merry-go-round?  Explain it.

2. What will be your observation when you are standing at the centre of the merry-go-round. Explain it.

Asked by Topperlearning User 4th June 2014, 1:23 PM
Answered by Expert

The figure shows a ball tied at one end of a string, the other end of which is tied at the centre of merry-go-round which is rotating.  As the ball is left, the string becomes tight showing that it is under tension.  A person standing at M on the ground outside the merry-go-round finds that the ball is moving on a circular path (shown by dotted lines), while a person standing on the merry-g-round at A finds that the ball is stationary placed just in front of him at P.  The difference in the observations of two persons at M and A can be explained as follows:

Explanation :

1. For the person outside the merry-go-round i.e. at M, the ball moves in a circular path because the tension in the string provides the centripetal force needed for circular motion.

2. But for the person at A, following two forces act on the ball : (i) the tension in the string towards the centre of merry-go-round and (ii) the centrifugal force away from the centre.  The two forces being equal and opposite, so the net force on the ball is zero and hence it remains stationary.

Answered by Expert 4th June 2014, 3:23 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp