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CBSE Class 11-science Answered

A ball is kicked at an angle of 30 degrees with the verticAl, if the horizontal component of its velocity is 19.6m/s. Find the max. height and horizontal plane.
Asked by rnsahoo67 | 17 Aug, 2017, 09:52: PM
answered-by-expert Expert Answer
 
 
1) The ball is kicked with 30° with vertical. So, its angle with horizontal is 60°.
 
2) Calculate the speed of projection by using cosine angle. uh = u cosθ. So, u = 19.6 × 2 = 39.2 m/s
 
3) Calculate maximum height using H = u2sin2θ/2g. You will get 58.8 m.
 
4) Calculate maximum range using R = u2sin2θ/g. You will get 135.8 m.
Answered by Romal Bhansali | 18 Aug, 2017, 11:26: AM

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