NEET Class neet Answered
A ball is dropped from certain height such that distance traveled in last second = distance travelled in first 3 second find its height
Asked by Navjot0315 | 28 Jul, 2019, 12:42: PM
Expert Answer
Distance travelled in first 3 seconds, S3 = (1/2)×g×t2 = (1/2)×9.8×3×3 = 44.1 m .....................(1)
let the ball takes n second to reach the ground.
For the travel of last second duration, its initial speed un-1 = g×t = 9.8×(n-1)
Hence distance travelled in last second = un-1 × t + (1/2)g×t2 = 9.8×(n-1) + (1/2)×9.8 ......................(2)
By equating eqn.(1) and eqn.(2), we get n :- 9.8×(n-1) + (1/2)×9.8 = 44.1 .....................(3)
By solving eqn.(4), we get n = 5
Hence the total height = (1/2)×9.8×5×5 = 122.5 m ....................(4)
Answered by Thiyagarajan K | 28 Jul, 2019, 01:08: PM
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