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CBSE Class 9 Answered

A and B are two friends. A is elder to B by 5 years. B's sister C is half the age of B while A's father D is 8 years older than twice the age of B. If the present age of D is 48 years, find the present ages of A, B and C.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

Let the age of the sister C be x years

Age of B = 2x years

Age of A = (2x + 5) years

Age of D, A's father = [2 (2x) + 8]

= 4x + 8

According to the question:

4x + 8 = 48

x = 10

Therefore,

Age of C = x = 10 yrs

Age of B = 2x = 20 yrs

Age of A = 2x + 5 = 25 yrs.

Answered by | 04 Jun, 2014, 03:23: PM

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