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A and B are ideal gases . The molecular weights of A and B are in the ratio of 1:4.The pressure of a gas mixture containing equal weights of A and B is p atm . What is the partial pressure (in atm ) of B in the mixture. (a)p/5 (b)p/2 (c)p/2.5 (d)3p/4
Asked by Balbir | 21 Jul, 2019, 01:39: PM
answered-by-expert Expert Answer
Given:
 
Molecular weights of gases A and B are in the ratio of 1:4.
 
Let,
 
Molecular weight of gas A = 'x'
 
Molecular weight of gas B = '4x'
 
The mixture gases conatins equal weights of gas A and gas B
 
Let,
 
Weight of gas A = Weight of gas B = 'm' gm
 
Let total pressure be 'P'
We know
 
To calculate the partial pressure of gas B in the mixture, lets first calculate the mole fraction of gas B.
 
Mole fraction of gas B 
 
equals space fraction numerator begin display style bevelled fraction numerator straight m over denominator 4 straight x end fraction end style over denominator begin display style bevelled fraction numerator straight m over denominator 4 straight x end fraction plus bevelled straight m over straight x end style end fraction equals space 1 fifth straight P subscript straight B space equals space Mole space fraction space of space straight B space cross times space Total space pressure space space space space space equals straight P over 5
Answered by Varsha | 21 Jul, 2019, 11:22: PM

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