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CBSE Class 12-science Answered

(a) A reaction is second order in A and first order in B. (i)Write the differential rate equation. (ii)How is the rate affected on increasing the concentration of A three times? (iii) How is the rate affected when the concentrations of both A and B are doubled? (b)A first order reaction takes 40 minutes for 30% decomposition. Calculate t1/2 for this reaction. (Given log 1.428 = 0.1548)   OR   (a)For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction. (b)Rate constant 'k' of a reaction varies with temperature 'T' according to the equation: Where Ea is the activation energy. When a graph is plotted for log k Vs straight line with a slope of -4250 K is obtained. Calculate 'Ea' for the reaction. (R = 8.314 JK-1 mol-1)
Asked by Topperlearning User | 22 Jun, 2016, 09:19: AM
answered-by-expert Expert Answer

(a)(i)

Differential rate equation: Rate =

 

(ii) On increasing the concentration of A three times as 3A:

Rate'=

I.e. New rate is 9 times the initial rate.

 

(iii) On increasing the concentration of A and B as 2A and 2B:

Rate"=

8 times the initial rate.

 

(b)

Now, it takes 40 min for 30% decomposition i.e. reactant left after 40 min is 70% of its initial concentration.

Or

 

Case 1: If 't' is the time required for 99% completion then x = 99% of a

Case 2: If 't' is the time required for 90% of completion then x = 90% of a

Therefore, the time required for 99% completion of 1st order reaction is twice the time required for 90% completion.

 

(b)

Ea is Activation energy

The above equation is like y = mx + c where if we plot y v/s x we get a straight line with slope 'm' and intercept 'c'.

So, slope is equal to =

Answered by | 22 Jun, 2016, 11:19: AM
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