ICSE Class 10 Answered
A 4m long rod of negligible weight is to be balanced about a point 126cm from one end. A load of 18kgf is suspended at a point 60cm from the support on shorter arm.
(a) A weight W is placed 250cm from the support on the longer arm. Find W.
(b) If W=5kgf, where must it be kept to balance the rod?
Asked by Tarangini Boedoloi | 18 Jul, 2012, 10:31: PM
Expert Answer
The situation is expressed in the diagram shown below:
(a) Here x = 250 cm
Using balance of moments due to weights about the point of balance:
18 x 60 = W x 250
W = 4.32 kgf
(b) Here W= 5 kgf
thus again
18 x 60 = 5 x
x = 216 cm
Answered by | 18 Jul, 2012, 10:58: PM
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